Résoudre :
1
\(\begin{cases}x\equiv 2 \hfill(\mathrm{mod}\, {140}) \cr x\equiv -3 \hfill(\mathrm{mod}\, {99}).\end{cases}\)
2
\(\begin{cases}x\equiv 3 \hfill(\mathrm{mod}\, 4)\cr x\equiv-2 \hfill(\mathrm{mod}\, 3)\cr x\equiv 7 \hfill(\mathrm{mod}\, 5).\end{cases}\)