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Soit \(\theta\in{]0,\pi[}\). Montrer que \(\int_{t=0}^1 \frac{d t}{e^{-i\theta}-t} = \sum_{n=1}^\infty \frac{\exp(in\theta)}n\).
Soit \(\theta\in{]0,\pi[}\). Montrer que \(\int_{t=0}^1 \frac{d t}{e^{-i\theta}-t} = \sum_{n=1}^\infty \frac{\exp(in\theta)}n\).