exo7 4264

1

1sin⁡xsin⁡4x−14sin⁡x+18ln⁡∣1−sin⁡x1+sin⁡x∣−122ln⁡∣1−2sin⁡x1+2sin⁡x∣tan⁡x1+tan⁡xx2−12ln⁡∣cos⁡x+sin⁡x∣cos⁡xcos⁡2xsin⁡xcos⁡2x2+122Arcsin(2sin⁡x)1sin⁡x+sin⁡2x16ln⁡(1−cos⁡x)+12ln⁡(1+cos⁡x)−23ln⁡∣1+2cos⁡x∣1cos⁡xcos⁡2x2Argth(2sin⁡x)−Argth(sin⁡x)1sin⁡xsin⁡x(1+sin⁡x)−21−sin⁡xsin⁡x+2Arctan1−sin⁡x2sin⁡x(poser u=1/sin⁡x)asin⁡xcos⁡xcos⁡2x−a2sin⁡2x−Arctan(cos⁡2x−a2sin⁡2xa)\begin{array}{ll} \frac1{\sin x\sin 4x} & -\frac1{4\sin x} + \frac18 \ln\Bigl| \frac{1-\sin x}{1+\sin x} \Bigr| - \frac1{2\sqrt2} \ln\biggl| \frac{1-\sqrt2\sin x}{1+\sqrt2\sin x} \biggr| \cr \frac{\tan x}{1+\tan x} & \frac x2 - \frac12 \ln|\cos x + \sin x| \cr \cos x\sqrt{\cos 2x} & \frac{\sin x\sqrt{\cos 2x}}2 + \frac1{2\sqrt2} \Arcsin(\sqrt2\sin x) \cr \frac1{\sin x + \sin2x} & \frac16 \ln(1-\cos x) + \frac12 \ln(1+\cos x)- \frac23 \ln|1+2\cos x| \cr \frac1{\cos x\cos 2x} & \sqrt2\Argth(\sqrt2\sin x) -\Argth(\sin x) \cr \frac1{\sin x\sqrt{\sin x(1+\sin x)}} & -2\sqrt{\frac{1-\sin x}{\sin x} } + \sqrt2\Arctan\sqrt{\frac{1-\sin x}{2\sin x} } \quad(\text{poser } u = 1/\sin x) \cr \frac{a\sin x}{\cos x\sqrt{\cos^2x-a^2\sin^2x}} & -\Arctan\biggl(\frac{\sqrt{\cos^2x-a^2\sin^2x}}a \biggr) \cr \end{array}

Exercice 9axm

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