exo7 4266

1

xkln⁡xxk+1k+1(ln⁡x−1k+1)ln⁡(1+x2)xln⁡(1+x2)−2x+2Arctanxx2+ax2+1Arctanx12((2x+(a−1)Arctanx)Arctanx−ln⁡(1+x2))(1−1x)e1/xxe1/xxcos⁡2xxtan⁡x+ln⁡∣cos⁡x∣1ex−12Arctanex−1Arctanx+1x+3(x+2)Arctanx+1x+3−ln⁡(x+1+x+3 )Arcsinxx+1xArcsinxx+1−x+ArctanxeArcsinxx+1−x22eArcsinxx(cos⁡2x)e−xe−x50((3−5x)cos⁡2x+(4+10x)sin⁡2x−25(x+1))(x2+x+1)e2xcos⁡x(2x25+4x25+39125)e2xcos⁡x+(x25−3x25+27125)e2xsin⁡x\begin{array}{ll} x^k\ln x & \frac{x^{k+1}}{k+1} \Bigl(\ln x - \frac1{k+1} \Bigr) \cr \ln(1+x^2) & x\ln(1+x^2) -2x + 2\Arctan x \cr \frac{x^2+a}{x^2+1} \Arctan x & \frac12 \bigl( (2x+(a-1)\Arctan x)\Arctan x - \ln(1+x^2)\bigr) \cr \Bigl(1-\frac1x \Bigr)e^{1/x} & xe^{1/x} \cr \frac x{\cos^2x} & x\tan x + \ln|\cos x| \cr \frac1{\sqrt{e^x-1}} & 2\Arctan\sqrt{e^x-1} \cr \Arctan\sqrt{\frac{x+1}{x+3}} & (x+2)\Arctan\sqrt{\frac{x+1}{x+3}} - \ln\bigl( \sqrt{x+1} + \sqrt{x+3}\, \bigr) \cr \Arcsin\sqrt{\frac x{x+1}} & x\Arcsin\sqrt{\frac x{x+1}} - \sqrt x + \Arctan \sqrt x \cr e^{\Arcsin x} & \frac{x+\sqrt{1-x^2}}2 e^{\Arcsin x} \cr x(\cos^2x)e^{-x} & \frac{e^{-x}}{50} \bigl( (3-5x)\cos 2x + (4+10x)\sin 2x - 25(x+1) \bigr) \cr (x^2+x+1)e^{2x}\cos x & (\frac{2x^2}5 + \frac{4x}{25} + \frac{39}{125} )e^{2x}\cos x + (\frac{x^2}5 - \frac{3x}{25} + \frac{27}{125} )e^{2x}\sin x \cr \end{array}

Exercice JSfO

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