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Soient \({f,g} : {[a,b]} \to \R\) continues. On suppose que : \(\forall\ x \in {[a,b]},\ \exists\ y \in [a,b] \text{ tq } f(x) = g(y)\).
Montrer qu’il existe \(x \in {[a,b]}\) tel que \(f(x) = g(x)\).
Soient \({f,g} : {[a,b]} \to \R\) continues. On suppose que : \(\forall\ x \in {[a,b]},\ \exists\ y \in [a,b] \text{ tq } f(x) = g(y)\).
Montrer qu’il existe \(x \in {[a,b]}\) tel que \(f(x) = g(x)\).